On 8/7/2012 11:50 AM, Mukesh wrote:
...
> I've a very large number (num) for the loop counter. Inside I've an
> IF loop which will be iterated only every nth divison (num/n) of the
> loop counter. Obviously num/n may not be an integer, so every closest
> nth divison.
>
> sample code......
>
> num = 999999; % some large number n = 41; for j = 1:n; cntr(j) =
> round(num/n*j); end k = 0; for i = 1:num % some code here if
> sum(i==cntr) % some code here k = k + 1; disp(['Loop No:'
> sprintf('%7.0f',i)... ' IF No:' sprintf('%3.0f',k)... ' % Done:'
> sprintf('%5.1f',i/num*100)]); end end % Code ends here
>
> I don't want to create another for loop for generating the cntr
> vector.
>
> How can I achieve the same without creating the cntr loop?
Well, you don't need a look to prestore cntr...
cntr=round(num./n.*[1:n]);
Then
k = 1;
for i = 1:num
if sum(i==cntr(i))
% some code here
k = k + 1;
...
end
end
or, there's really no reason to precompute itjust compute it on the fly...
k = 1;
cntr=round(num/n);
for i = 1:num
if sum(i==cntr)
% some code here
k = k + 1;
cntr=round(num/n*k);
...
end
end

