MATLAB and Simulink resources for Arduino, LEGO, and Raspberry Pi

Learn moreOpportunities for recent engineering grads.

Apply Today2520 is the smallest number that can be divided by each of the numbers from 1 to 10 without any remainder.

What is the smallest positive number that is evenly divisible by all of the numbers from 1 to input number?

Thank you to Project Euler Problem 5

117 correct solutions
79 incorrect solutions

Last solution submitted on Jul 18, 2014

3 players like this problem

2 Comments

blaat
on 14 Feb 2012

What it does: it finds the maximum number of occurrences for each prime number smaller than x in the factorisations of the numbers 1:x (e.g., for x = 10, the maximum number of occurrences for 2 is 3, since 2*2*2 = 8). If the product of all prime factors taken to the power of their maximum # of occurrences is then taken, the smallest number that is divisible by 1:10 is obtained. So for x = 10: 2 * 2 * 2 * 3 * 3 * 5 * 7 = 2520.

Alfonso Nieto-Castanon
on 14 Feb 2012

nice

1 Comment

Franck Dernoncourt
on 3 Feb 2012

This code works but the server is too slow...

1 Comment