Crop part of an image

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Hamed
Hamed on 18 Apr 2013
Commented: Ahmed Fasih on 21 Jun 2016
Hi there.
i've an image : (120 * 160 px)
I want to crop part of that image where number is.
Finally result must be : (22 * 39 px)
Thank you for your help.

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Answers (1)

Jan
Jan on 18 Apr 2013
Edited: Jan on 18 Apr 2013
You did not explain the type of the image variable. It might be a gray-scale image of type UINT8. Row a 3D array of an RGB image the procedure must be modified.
[row, col] = find(img);
cropped = img(min(col):max(col), min(row):max(row));
Note that the image might be transposed when it is displayed, so perhaps you have to swap row and col.
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Image Analyst
Image Analyst on 19 Apr 2013
Jan's code works for binary images. An alternate method would be to use regionprops() to get the bounding box, then use imcrop().
Ahmed Fasih
Ahmed Fasih on 21 Jun 2016
Flipped row & col.
>> z = blkdiag(zeros(1,3),[1 2; 3 0], zeros(3,1))
z =
0 0 0 0 0 0
0 0 0 1 2 0
0 0 0 3 0 0
0 0 0 0 0 0
0 0 0 0 0 0
0 0 0 0 0 0
>> [row, col]=find(z)
row =
2
3
2
col =
4
4
5
>> z(min(row):max(row), min(col):max(col))
ans =
1 2
3 0

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