i am facing a problem plotting this function
objfun244.m
function f=objfun244(tp) % The objective function: total cost per unit time if replacement interval is tp % Assumption: The smallest time unit is week.
% f: total cost per unit time % tp: Length of the time interval in Weeks (preventive replacement interval)
global Cp Cf % cost of preventive replacement and failure replacement, respectively T =ceil(tp);
% f: total cost per unit time C_tp f=(Cp+Cf*HT(T))/tp;
% % Test % objfun244(4)
then on another .m file which is called plotting2.m here is the code i wrote
clear all;
clc;
t = i:1:12;
plot(t,objfun244(t));
grid on
xlabel('t')
ylabel('COST')
---------------------------------------
there is another function called H T , here is its code
function H=HT(T) % The recursive function H(T) % Calculate the Expected number of failures in (0,T], for Weibull % Distribution % Assumption: T's unit is week, the smallest time unit.
% H: the Expected number of failures in (0,T] % T: length of the time interval in weeks (preventive replacement interval) % T is a nonnegative integer: 0, 1, 2, 3, ...
global Al Be % Alpha and Beta for the Weibull distribution, respectively % ##### global HT_vec HT_flag % Calculated H(T) values: HT_flag(T)=1 if it has been calculated
H=0; % H(0)=0: initial value
if T<0.001
% H=0; % If T=0, H(T)=0;
elseif HT_flag(T)>0
% If HT(T) has been calculated, used the saved value
H=HT_vec(T); % Assign the value from HT_vec
else
% Otehrwise, recursively calculate H(T)
% i: time from 0 to T-1
for i=0:(T-1)
H=H+(1+HT(T-i-1))*(wblcdf(i+1,Al,Be)-wblcdf(i,Al,Be)); % #####
end
% Save the calculated H(T) value
HT_vec(T)=H;
HT_flag(T)=1;
end----------------------------------------------------
i got error : ??? Subscript indices must either be real positive integers or logicals.
Error in ==> HT at 20 elseif HT_flag(T)>0
Error in ==> objfun244 at 12 f=(Cp+Cf*HT(T))/tp;
Error in ==> plotting2 at 11 plot(t,objfun244(t));
-----------------------------
pleaseeee hellpppppp
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The problem is here:
clear all;
clc;
t = i:1:12;
Did you mean
t = 1:12;
function H=HT2(T) % The recursive function H(T) % Calculate the Expected number of failures in (0,T], for Weibull % Distribution % Assumption: T's unit is week, the smallest time unit.
% H: the Expected number of failures in (0,T] % T: length of the time interval in weeks (preventive replacement interval) % T is a nonnegative integer: 0, 1, 2, 3, ...
global Al Be % Alpha and Beta for the Weibull distribution, respectively % ##### global HT_vec HT_flag % Calculated H(T) values: HT_flag(T)=1 if it has been calculated
T= 2:1:12;
H=0; % H(0)=0: initial value
for i2 = 1:length(T)
if HT_flag(T(i2))>0
% If HT(T) has been calculated, used the saved value
H=HT_vec(T(i2)); % Assign the value from HT_vec
else
% Otehrwise, recursively calculate H(T)
% i: time from 0 to T-1
for i=0:(T(i)-1)
H=H+(1+HT2(T(i)-i-1))*(wblcdf(i+1,Al,Be)-wblcdf(i,Al,Be)); % #####
end
% Save the calculated H(T) value
HT_vec(T(i))=H;
HT_flag(T(i))=1;
end
endplot(T,HT2(T));
grid on
xlabel('t')
ylabel('COST')
Please use the {} Code button when pasting code. And be specific in your questions. What did the error message say? I bet it is here:
for i=0:(T(i)-1)
In this line you are defining i for the first time (masking MATLAB's imaginary unit, I might add), so you cannot refer to it in the same line.
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