Cell Array

Asked by Andrés on 24 Apr 2012
Latest activity Commented on by Andrei Bobrov on 24 Apr 2012

Hello, is a simple question.

How can I remove repeated vectors from a cell array. Example:

Given a cell array {[1,2,3] [2,4] [1] [1,2,3] [5] [2,4] [1]}

I want the result:

{[1,2,3][2,4][1][5]} Thank you

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Andrés

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3 Answers

Answer by Wayne King on 24 Apr 2012

One way:

   x = {[1,2,3] [2,4] [1] [1,2,3] [5] [2,4] [1]};
   y = cellfun(@num2str,x,'uniformoutput',false);
   xnew = unique(y);
   xnew = cellfun(@str2num,xnew,'uniformoutput',false);

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Wayne King
Answer by Andrei Bobrov on 24 Apr 2012 
y = cellfun(@(y)[y,zeros(1,max(cellfun('size',x,2)) - numel(y))],x,'un',0);
y = cat(1,y{:});
[a,b] = unique(y,'rows','first');
[ii,ii] = sort(b);
out = x(b(ii));

EDITED

[a,n,n] = unique([x{:}])
nn = cellfun('size',x,2);
y = mat2cell(n,1,nn);
y = cellfun(@(y)[y,k*ones(1,max(nn) - numel(y))],y,'un',0);
y = cat(1,y{:});
[a,b] = unique(y,'rows','first')
[ii,ii] = sort(b);
out = x(b(ii));

2 Comments

Jan Simon on 24 Apr 2012

Does this fail to process {[1], [1,0]}?

Andrei Bobrov on 24 Apr 2012

Hi Jan! Corrected.

Andrei Bobrov
Answer by Jan Simon on 24 Apr 2012

A dull FOR loop appraoch:

x = {[1,2,3] [2,4] [1] [1,2,3] [5] [2,4] [1]};
n = numel(x);
v = true(1, numel(x));
for i = 2:n
  tmp = x{i};
  for j = 1:i-1
    if isequal(x{j}, tmp)
      v(i) = false;
      break;  % Leave j loop
    end
  end
end
out = x(v);

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Jan Simon

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