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Help with this code.

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Abhinav
Abhinav on 26 Feb 2015
Closed: MATLAB Answer Bot on 20 Aug 2021
for i = 1:5
b1(i,:)= round(((1860-0)*(rand(1)))+0)
end
b1
for i = 1:5
b2(i,:)= round(((1908-0)*(rand(1)))+0);
end
b2
for i = 1:5
b3(i)= round(((1316-0)*(rand(1)))+0);
end
b3
for i = 1:5
b4(i)= round(((2940-0)*(rand(1)))+0);
end
b4
for i=1:5
b5(i,:)= round(((1860-0)*(rand(1)))+0);
end
b5
for i=1:5
b6(i,:)= round(((1860-0)*(rand(1)))+0);
end
b6
In this code I want a condition that if b5+b6=b1 then only it should execute the result otherwise search for solutions until this criterion matches. Please help me with this.
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Abhinav
Abhinav on 26 Feb 2015
This is a supply chain problem. b1 are the set of products which are produced by manufacturer. b5 and b6 are the quantities of product sent to two different customers. Hence I have to generate b1 first.
Guillaume
Guillaume on 26 Feb 2015
Edited: Guillaume on 26 Feb 2015
Then generate b6 as b1-b5?
Given two of b1, b5 or b6 there is only one of the other that work, so why generate random invalid sets for that other, when you could just calculate the unique set that would work.

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Answers (1)

Guillaume
Guillaume on 26 Feb 2015
Edited: Guillaume on 26 Feb 2015
As per my comment, it seems very silly to generate random sets that have no way of working when you could just generate sets that always work, so this will get you there faster:
invalidset = true;
while invalidset
b1 = randi([0 1860], 5, 1);
%... same for b2, b3, ...
b5 = randi([0 1860], 5, 1);
b6 = b1 - b5;
invalidset = any(b6 <0 | b6 > 1860);
end
But if you really want to waste time generating a random bunch of 3 sets that have no chance of working, it's:
invalidset = true;
while invalidset
b1 = randi([0 1860], 5, 1);
%... same for b2, b3, ...
b5 = randi([0 1860], 5, 1);
b6 = randi([0 1860], 5, 1);
invalidset = ~isequal(b1, b5 + b6);
end
First option took 0.007044 seconds to generate a set on my machine. Second option is still running after a minute.

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