How to enter this program?

3 views (last 30 days)
Colton
Colton on 25 Oct 2014
Commented: per isakson on 26 Oct 2014
Hello, I have tried unsuccessfully for a couple hours to enter a program that loops until a number that is even, divisible by both 13 and 16, and whose square root is greater than 120 is found. I have reached a wall, so I have come to ask for help. Would using a while statement be the first step? Please don't solve this problem, I only ask for help getting it going. Yes, this is basic stuff, but I still have little understanding on it.

Sign in to answer this question.

Accepted Answer

Roger Stafford
Roger Stafford on 25 Oct 2014
You need to translate each of those conditions into a matlab logical proposition. For example if n is an integer you are investigating, try dividing it by 13, then comparing the 'round' of the quotient with the original quotient to see if it is still an integer after the division. And yes, the 'while' function is the right thing to use here. Keep it looping until all the conditions turn out to be true for the same integer, for which you can make great use of the "&" operation.
  5 Comments
Show 3 older comments
Rick Rosson
Rick Rosson on 25 Oct 2014
Try using || instead of &&.
Colton
Colton on 26 Oct 2014
@Rick, thank you. That fixed my issues and I was able to find the correct value! And thanks everyone else for the help!

Sign in to comment.

More Answers (2)

Rick Rosson
Rick Rosson on 25 Oct 2014
Edited: Rick Rosson on 25 Oct 2014
Here is a faster and simpler approach:
a = 0;
while a < 120^2
a = a + 13*16;
end
  1 Comment
per isakson
per isakson on 26 Oct 2014
Note &nbsp "square root is greater than 120"

Sign in to comment.

per isakson
per isakson on 26 Oct 2014
Edited: per isakson on 26 Oct 2014
Try
>> factor( cssm )
ans =
2 2 2 2 2 5 7 13
where cssm is
function ix = cssm()
% chose a start value, which is larger than 120^2 and divisible by 16
ix = 120*120+16;
while ne( mod(ix,13), 0 )
ix = ix + 16;
end
end

Categories

Find more on Loops and Conditional Statements in Help Center and File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!